cbse ncert 10th mathematics
chapter 5 arithmetic progressions, exercise 5.4 optional exercise
5. A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete. Each step has a rise of (1/4) m and a tread of (1/2)m. Calculate the total volume of concrete required to build the terrace.
thinking of each step as a cuboid with length =50m, breadth =(1/2)m
and height (1/4)m for the first step with increase of (1/4)m for each further step
volume for first step
V1 = length * breadth * height =50*(1/2)*(1/4)
for second step
length =50m, breadth =(1/2)m, height =(1/4)+(1/4) =(1/2)m
volume for second step
V2 = length * breadth * height =50*(1/2)*(1/2)
for third step
length =50m, breadth =(1/2)m, height =(1/4)+(1/4)+(1/4) =(3/4)m
volume for second step
V2 = length * breadth * height =50*(1/2)*(3/4)
and so on
so total volume
= [50*(1/2)*(1/4)]+[50*(1/2)*(1/2)]+[50*(1/2)*(3/4)] +... (15 terms)
=50*(1/2) { (1/4) +(1/2) +(3/4) + ....(15 terms) }
=25 *{ (1/4) +(1/2) +(3/4) + ....(15 terms) } ,
using sum of n=15 terms of an AP with first term a=(1/4), d =(1/4) for { ...}
Sn = (n/2)*[ 2a + (n-1)d ]
total volume = 25 *{ (15/2) *[2(1/4) +(15-1)(1/4) ] }
=25* { (15/2) [ (1/2)+ (14/4) ] }
=25* {15/2 [(1/2) +(7/2)}
=25* {(15/2)*(4)}
=25*15*2=750 cubic metres
cbse ncert 10th mathematics
chapter 5 arithmetic progressions, exercise 5.3
exercise 5.3
20. In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato,and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
the distance covered to bring the first potato to the bucket = 5+5=10m
After that ,the distance covered for bringing the second potato to the bucket
=5 +3 + 3 +5 =16m
After that ,the distance covered for bringing the third potato to the bucket
=5 +3 + 3 +3+ 3 +5 =22m
and so on for the 10 potatoes
so total distance = 10 +16 +22 + ... (10 terms )
using sum of n=10 terms of an AP with first term a=10 , d=t2-t1=16-10=6
Sn = (n/2)*[ 2a + (n-1)d ]
total distance = 10 +16 +22 + ... (10 terms )
= (10/2)*[2(10)+(10-1)(6)]
=5*74 =370m
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ncert cbse 10th mathematics
chapter 5 arithmetic progressions
exercise 5.4 optional exercise
Which term of the AP : 121, 117, 113, . . ., is its first negative term?
2. The sum of the third and the seventh terms of an AP is 6 and their
product is 8. Find the sum of first sixteen terms of the AP.
3. A ladder has rungs 25 cm apart. The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and last rungs are [ 2 and(1/2) ]m apart, what is the length of the wood required for the rungs?
4. The houses of a row are numbered consecutively from 1 to 49. Show that there is a value of x such that the sum of the numbers of the houses preceding the house numbered x is equal to the sum of the numbers of the houses following it. Find this value of x.
solution5. A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete. Each step has a rise of (1/4) m and a tread of (1/2)m. Calculate the total volume of concrete required to build the terrace.
chapter 5 arithmetic progressions, exercise 5.3
exercise 5.3
20. In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato,and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
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