find the derivative of sqrt(3x-2) from first principles.
another example
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Tuesday, September 30, 2008
Monday, September 29, 2008
orthogonal trajectory of y = (k/x)
find the orthogonal trajectory of y = (k/x)
first we find the diff. equation of the given family
y=(k/x) -----------(1)
diff. w.r.t. x
y' = -k / (x²)---------(2)
eliminating k , divide (2) by (1)
y' / y = -1/x ---------(3)
(3) is the diff. equation of the given family.
replace y with -1/y' in (3) to get the diff. equation of the orthogonal trajectory
diff. equation of the orthogonal trajectory is
-yy' = -1/x
y(dy/dx) = 1/x
ydy =xdx
integrating and simplifying, we see that the orthogonal trajectory is
x² - y² = C
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first we find the diff. equation of the given family
y=(k/x) -----------(1)
diff. w.r.t. x
y' = -k / (x²)---------(2)
eliminating k , divide (2) by (1)
y' / y = -1/x ---------(3)
(3) is the diff. equation of the given family.
replace y with -1/y' in (3) to get the diff. equation of the orthogonal trajectory
diff. equation of the orthogonal trajectory is
-yy' = -1/x
y(dy/dx) = 1/x
ydy =xdx
integrating and simplifying, we see that the orthogonal trajectory is
x² - y² = C
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to find the equation of a circle with center (2,-6); tangent to the y-axis
Find the equation of the circle with center(2,-6) and tangential to the y-axis.
Since the y-axis is a tangent to the circle,
radius of the circle,r =|x-coordinate of the centre| = 2
equation of the circle is
(x-2)² +(y+6)² = 2²
formulae on circles
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Since the y-axis is a tangent to the circle,
radius of the circle,r =|x-coordinate of the centre| = 2
equation of the circle is
(x-2)² +(y+6)² = 2²
formulae on circles
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Saturday, September 27, 2008
beware of drm
If you buy music loaded with drm, you might face problems later on ,if the company maintaining the drm servers decides to shut down the servers due to decreasing profits or for any other silly reason.If the servers are shut down, then "if you do not back up your files before this date, you will no longer be able to transfer your songs to other computers or access your songs after changing or reinstalling your operating system or in the event of a system crash".
interesting example:
http://www.boingboing.net/2008/09/26/walmart-shutting-dow.html
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interesting example:
http://www.boingboing.net/2008/09/26/walmart-shutting-dow.html
disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.
to find the square root of a cormplex number
to find sqrt(3-4i)
let sqrt(3-4i)= x+iy
squaring 3-4i = x² -y² +2ixy
equating real parts , x² -y² =3
equating imaginary parts 2xy = -4
(x² +y²)² =(x² - y²)² + (2xy)² = 9 +16 = 25
therefore
(x² +y²) = 5 ----------(1)
also
x² -y² =3-----------(2)
(1) +(2) implies
2 x² = 8 or x² = 4 or x = ± 2
using 2xy = -4
if x=2 , y = -1
if x = -2 , y =1
so sqrt(3-4i) = 2-1 i or-2 + 1i
sqrt(3-4i) = ± (2- i )
some notes on complex numbers
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let sqrt(3-4i)= x+iy
squaring 3-4i = x² -y² +2ixy
equating real parts , x² -y² =3
equating imaginary parts 2xy = -4
(x² +y²)² =(x² - y²)² + (2xy)² = 9 +16 = 25
therefore
(x² +y²) = 5 ----------(1)
also
x² -y² =3-----------(2)
(1) +(2) implies
2 x² = 8 or x² = 4 or x = ± 2
using 2xy = -4
if x=2 , y = -1
if x = -2 , y =1
so sqrt(3-4i) = 2-1 i or-2 + 1i
sqrt(3-4i) = ± (2- i )
some notes on complex numbers
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Friday, September 26, 2008
to find cot(x ) if you are given that sin(x)=2/3 by drawing a triangle
find cot(x ) if you are given that sin(x)=2/3 and that x is acute.
draw a rt. triangle with one angle as x (not the right angle)
choose the opp. side as 2 and hypotenuse as 3 so that the third side is
sqrt(5) (using pythagoras theorem)
so cot(x) = (sqrt 5) /2
some trigonometry formulae
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draw a rt. triangle with one angle as x (not the right angle)
choose the opp. side as 2 and hypotenuse as 3 so that the third side is
sqrt(5) (using pythagoras theorem)
so cot(x) = (sqrt 5) /2
some trigonometry formulae
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If n is an integer, show that one of the integers n, n+2, or n+4 is divisible by 3.
If n is an integer, show that one of the integers n, n+2, or n+4 is divisible by 3.
solution:
If n is a multiple of 3, then there is nothing more to prove.
Suppose n is not a multiple of 3, then n must be of the form
n =3k+1 or n = 3k+2, for some integer k
if n=3k+1,
then n+2 = (3k+1)+2 = 3k+3 = 3(k+1) = multiple of 3
if n = 3k+2,
then n+4 = 3k+6 = 3(k+2) =multiple of 3
hence the result
some other math problems
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solution:
If n is a multiple of 3, then there is nothing more to prove.
Suppose n is not a multiple of 3, then n must be of the form
n =3k+1 or n = 3k+2, for some integer k
if n=3k+1,
then n+2 = (3k+1)+2 = 3k+3 = 3(k+1) = multiple of 3
if n = 3k+2,
then n+4 = 3k+6 = 3(k+2) =multiple of 3
hence the result
some other math problems
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