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Tuesday, October 28, 2008

derivation of mean and variance of binomial distribution

derive the mean and variance of the binomial distribution
now to find the variance, we rewrite x^2 as x(x-1) +x before we start out



for explanation of mean of poisson distribution try the link mean of poisson distribution

for explanation of mean and variance of discrete uniform distribution try the link mean of the discrete uniform distribution



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14 comments:

  1. thanx man .... d derivation n my book ended in just 2 lines !!!

    ReplyDelete
  2. thanx man .... d derivation n my book ended in just 2 lines !!!

    ReplyDelete
  3. thanks dude..............

    ReplyDelete
  4. Thank you!! This is just what I was looking for!

    ReplyDelete
  5. No matter when you posted, its still helpful to me, thanks. I understood everything as the steps are easy to follow.

    ReplyDelete
  6. Thanks Alot.. As A B.Tech 2nd Year Student it helps me alot!

    ReplyDelete
  7. Thank u vry much...

    ReplyDelete
  8. Deviation from mean x-μ
    Square deviation from mean Sum of the squares of deviation from mean=∑▒〖(x-μ)〗^2
    The mean sum of the squares of deviation from the mean (μ) is=1/n ∑▒〖(x-μ)〗^2
    The root mean square deviation is = sqrt(1/n ∑▒〖(x-μ)〗^2 )



    The standard deviation is nothing but the root mean square deviation .

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