auto ad

Friday, October 23, 2009

word problem 5

The area of a right angle triangle is 63 sq.cm. The length of the base of the triangle is 5 cm. more than the altitute of the triangle. Find the length of the altitute of the triangle.

let the length of the altitute be x cm.
therefore length of the base is ( x + 5) cm.

area of the right angled triangle is (1/2) * base * altitude = (1/2)(x)( x + 5 )
but given that area = 63
therefore
(1/2)(x)( x + 5 ) = 63

or x(x+5) = 126

or
x ² + 5x - 126 = 0

solving
x ² + 14x -9x - 126 = 0
x( x +14 ) - 9( x + 14 ) = 0
( x - 9 ) ( x + 14 ) = 0

x = 9 or x = -14

ignoring negative value for x

x = 9 cm

therefore length of the altitude = 9 cm.


other word problems with some explanation


------------------------------------------------------------


disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work





No comments:

Post a Comment

please leave your comments