integral of 1 / [cos(x-a)cos(x-b)]
we will try to write the numerator in terms of the denominator
so introduce sin(a-b) in the numerator and denominator
note that (x-b)-(x-a) =a-b
so write sin(a-b) as sin[ (x-b)-(x-a) ] and expand using sin[A-B] formula
divide the numerator term by term with the denominator
reduce to terms involving sec and then integrate
study integration formulae a
free guide on integration or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students
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