finding n of binomial distribution given the probability from miscellaneous 12th cbse ncert mathematics

How
many times must a man toss a fair coin so that the probability of
having at least one head is more than 90%?

Let
n be the required number of times the man must toss a fair coin so
that the probability of having at least one head is more than 90%

Let
X be the number of heads obtained when the coin is tossed n times.

Assuming
X follows binomial distribution with

n=n

p
= (½)

q
= 1 – p = (½)

P[X=r]
=

_{n}C_{r }p^{r}q^{(n-r) }, r = 0,1,2,...,n
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link to index of other miscellaneous problems on probability of cbse ncert 12th mathematics

link to index of other miscellaneous problems on probability of cbse ncert 12th mathematics

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