finding n of binomial distribution given the probability from miscellaneous 12th cbse ncert mathematics
How
many times must a man toss a fair coin so that the probability of
having at least one head is more than 90%?
Let
n be the required number of times the man must toss a fair coin so
that the probability of having at least one head is more than 90%
Let
X be the number of heads obtained when the coin is tossed n times.
Assuming
X follows binomial distribution with
n=n
p
= (½)
q
= 1 – p = (½)
P[X=r]
= nCr prq(n-r) , r =
0,1,2,...,n
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link to index of other miscellaneous problems on probability of cbse ncert 12th mathematics
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link to index of other miscellaneous problems on probability of cbse ncert 12th mathematics
index of more problems on baye's theorem for ncert cbse mathematics
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