Suppose that 90% of people are right handed. What is the probability that at most 6 of a random sample of 10 people are right handed?

Let X be the number of people who are right handed out of a sample of 10 people.

Assuming X follows binomial distribution with

n = 10

p = (90/100) = (0.9) [given that 90% of people are right handed]

q = 1 - p = (0.1)

**index of more problems on baye's theorem for ncert cbse**

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