auto ad

Monday, December 26, 2016

miscellaneous problem 4 on binomial distribution

miscellaneous problem 4 on binomial distribution for cbse xii probability

Suppose that 90% of people are right handed. What is the probability that at most 6 of a random sample of 10 people are right handed?

Let X be the number of people who are right handed out of a sample of 10 people.

Assuming X follows binomial distribution with
n = 10
p = (90/100) = (0.9) [given that 90% of people are right handed]
q = 1 - p = (0.1)



 index of more problems on baye's theorem for ncert cbse class XII mathematics
disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work

No comments:

Post a Comment

please leave your comments