ncert cbse chapter 8 binomial theorem miscellaneous exercise
8.
find n if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of [(fourth root of 2) + {1/(fourth root of 3)}]^n is (sqrt6):1
in [{2^(1/4)}+{3^(-1/4)}]^n
T(r+1) = C(n.r)[ {2^(1/4)}^(n-r) ][{3^(-1/4)}^(r)]
for fifth term from the beginning
r=4
T(5) = C(n,4)[2^((n-4)/4)][3^(-(4)/4)] =C(n,4)[2^((n-4)/4)] / [3]
For finding the fifth term from the end in the given expansion, we interchange the terms and find the fifth term from the beginning of
[{3^(-1/4)} + {2^(1/4)} ]^n
t ' (5) = C(n,4) [3^( -(n-4)/4)][ 2^((4)/4)]=C(n,4) [3^( -(n-4)/4)] [2]
T(5) / t'(5) = [ 6^((n-4)/4) ] / [6^1]
(a^m)/(a^n) =a^(m-n)
[(n-4)/4] -[1] = [(n-8)/4]
T(5) / t'(5) = [6^( (n-8)/4 ) ]
using given ratio
[ sqrt(6) / 1] = [6^( (n-8)/4 ) ]
6^(1/2) = [6^( (n-8)/4 ) ]
(1/2) = ( (n-8)/4 )
4/2 = n-8
2=n-8
n=10
exercise 8.2
5. find the 4th term in the expansion of (x-2y)^12
n=12
T(r+1)=C(12,r) [x^(12-r)][ (-2y)^r]
for 4th term
put r=3
T(3+1) = C(12,3) [x^(12-3)][ (-2y)^3]
T(4) = 220*[x^9][-8y^3]
T(4)=(-1760)[x^9][y^3]
chapter 8 binomial theorem miscellaneous exercise
1.Find a , b and n in the expansion of (a+b)^n if the first three terms in the expansion are 729, 7290, 30375
2. Find a if the coefficients of (x^2) & (x^3) in the expansion of {(3+ax)^9} are equal
3.find the coefficient of {x^5} in the expansion of{(1+2x)^6}{(1-x)^7}
5.evaluate { (sqrt(3) + sqrt(2))^6 } - { (sqrt(3) - sqrt(2))^6 }
6.find the value of [(a^2)+sqrt{(a^2)-1}]^4 + [(a^2)-sqrt{(a^2)-1}]^4
7.find an approximate value of (0.99^5) using the first three terms of its expansion
8.find n if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of [(fourth root of 2) + {1/(fourth root of 3)}]^n is (sqrt6):1
solution
exercise 8.2
Q8) Find the middle terms in the expansion of [(x/3)+9y)]^10
5. find the 4th term in the expansion of (x-2y)^12
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