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Tuesday, August 4, 2020

If the different permutations of the word EXAMINATION are arranged in a dictionary how many words are there in this list before the first word starting with E

ncert cbse chapter7permutations miscellaneous exercise

4. If the different permutations of the word EXAMINATION are arranged in a dictionary how many words are there in this list before the first word starting with E

first arrange the 11 letters in alphabetical order

AA   2 A's

E

II  2 I's

M

NN 2 N's

O

T

X

Therefore before the first word starting with E, words starting with the letter
A will be arranged in alphabetical order in the dictionary.

fix one A in the first slot

remaining 10 letters contain 2 I's and 2 N's [ one of the 2 A's is used for the first slot ]

So number of words starting with the letter A

= [(10!)/ {(2!)*(2!)}] =907200

6.How many 6 digit numbers can be formed using 0,1,3,5,7,9 which are divisible by 10 and no digit is repeated?

The one's place should contain 0 for the number to be divisible by 10
Fix the digit 0 in the one's place Therefore the one's place can be filled in only one way.
The other 5 slots can be filled in 5! = 120 ways

Answer = 1*120 = 120



ncert cbse 11th mathematics chapter  7 permutations exercise 7.3
11.In how many ways can the letters of the word PERMUTATIONS be arranged if
i)words start with P and end with S
ii)vowels are all together
iii)there are always 4 letters between P and S


ncert cbse 11th mathematics chapter  7 permutations miscellaneous exercise


1.How many words each of 2 vowels and 3 consonants can be formed using the letters of the word DAUGHTER



2. How many words of can be formed using all the letters of the word
 EQUATION  so that the vowels and consonants occur together?

4. If the different permutations of the word EXAMINATION are arranged in a dictionary how many words are there in this list before the first word starting with E

6.How many 6 digit numbers can be formed using 0,1,3,5,7,9 which are divisible by 10 and no digit is repeated?



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