ncert cbse 11th limits and derivatives miscellaneous exercise
17.find the derivative of (sinx+cosx) / (sinx-cosx)
using quotient rule for differentiation
if y = (u/v)
dy/dx = [vu' - uv'] / [v^2]
u = sinx + cosx
v = sinx - cosx
u' = cosx - sinx
v' = cosx + sinx
y = (sinx+cosx)/sinx-cosx)
dy/dx ={(sinx-cosx)(cosx - sinx) -(sinx+cosx)(cosx + sinx)}/{(sinx-cosx)^2}
on simplification
dy/dx = -2{(sinx)^2 + (cosx)^2} / {(sinx-cosx)^2}
using trigonometry formula trigonometry identities
{(sinx)^2 + (cosx)^2} = 1
dy/dx = (-2) / {(sinx-cosx)^2}
18. find the derivative of (secx -1) / (secx+1)
using quotient rule for differentiation
if y = (u/v)
dy/dx = [vu' - uv'] / [v^2]
u = (secx -1)
v = (secx + 1)
u' = secx tanx
v' = secx tanx
y =(secx -1) / (secx+1)
dy/dx = [vu' - uv'] / [v^2]
dy/dx = [(secx +1)(secx tanx) - (secx -1)(secx tanx) ] / [(secx + 1)^2]
on simplification
dy/dx = [2secx tanx] / [(secx + 1)^2]
13. limits and derivatives
miscellaneous exercise
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miscellaneous exercise
1.
(i) find the derivative of (-x) using first principles
solution
(ii) find the derivative of [ (-x)^(-1) ] using first principles
solution
(i) find the derivative of (-x) using first principles
solution
(ii) find the derivative of [ (-x)^(-1) ] using first principles
(iii)find the derivative of sin(x+1) using first principles
(iv) find the derivative of cos[x-(pi/8)] using first principles
solution
(iv) find the derivative of cos[x-(pi/8)] using first principles
solution
17.find the derivative of (sinx+cosx) / (sinx-cosx)
18. find the derivative of (secx -1) / (secx+1)
23.find the derivative of [(x^2)+1][cosx]
24. find the derivative of (a(x^2)+sinx )[p+qcosx]
29.
find the derivative of (x+secx)(x-tanx)
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