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Showing posts with label bayes theorem. Show all posts
Showing posts with label bayes theorem. Show all posts

Sunday, December 25, 2016

problem 10 and problem 11 of bayes theorem for ncert bayes theorem


Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4, she tosses a coin once and notes whether a head or tail is obtained. If she obtained exactly one head, what is the probability that she threw 1, 2, 3 or 4 with the die?

Let E1 be the event that the girl threw 1 or2 or 3,or 4 with the dice .

let E2 be the event that the girl threw 5 or 6 with the die.

let A be the event that the girl obtained exactly one head .


P( E1 ) = ( 4 / 6 ) { the girl threw 1 or2 or 3,or 4 with the dice }

P( E2 ) = ( 2 / 6 ) { the girl threw 5 or 6 with the die }

P( A / E1 ) = ( 2 / 4 ) [ {HT,TH} out of {HT,TH,TT,HH}]

P( A / E2 ) = ( 3 / 8 ) [ {HTT,THT,TTH} out of {HTT,THT,TTH,HHH,TTT,THH,HHT,HTH}]


Required probability = P [ she threw 1, 2, 3 or 4 with the die given that she obtained exactly one head ]

Required probability = P [ E1 / A ]




P ( E1 / A ) = [( 4/6)( 2/4)] / { [( 4/6)( 2/4) ] + [( 2 / 6 )( 3 / 8 )] }


P ( E1 / A ) =  [ (1/3) ] / {[(1/3)]+[1/8]} =  ( 8 / 11 )
index of more problems on baye's theorem for ncert cbse mathematics

problem 11
A manufacturer has three machine operators A, B and C. The first operator A produces 1% defective items, where as the other two operators B and C produce 5% and 7% defective items respectively. A is on the job for 50% of the time, B is on the job for 30% of the time and C is on the job for 20% of the time. A defective item is produced, what is the probability that it was produced by A?

Let E1 be the event that a selected item was produced by A .

let E2 be the event that a selected item was produced by B.

let E3 be the event that a selected item was produced by C.

let A be the event that the selected item was defective .


P( E1 ) = ( 50 / 100 )

P( E2 ) = ( 30 / 100 )

P( E3 ) = ( 20 / 100 )

P( A / E1 ) = ( 1 / 100 )

P( A / E2 ) = ( 5 / 100 )

P( A / E3 ) = ( 7 / 100 )


Required probability = P [ item was produced by A given that the item is defective ]

Required probability = P [ E1 / A ]


                  
P ( E1 / A ) = [( 50 / 100 )( 1 / 100 )] / { [(50/100)(1/100)]+[(30/100)(5/100)] +[(20/100)(7/100)] }


P ( E1 / A ) =  [ 50 ] / {[50]+[150]+[140]} =  ( 5 / 34 )

index of more problems on baye's theorem for ncert cbse mathematics

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bayes theorem problems 8 and 9 for cbse ncert

problem 8

A factory has two machines A and B. Past record shows that machine A produced 60% of the items of output and machine B produced 40% of the items. Further,2% of the items produced by machine A and 1% produced by machine B were defective. All the items are put into one stockpile and then one item is chosen at random from this and is found to be defective. What is the probability that it was produced by machine B?

Let E1 be the event that the chosen item was produced by machine A .

let E2 be the event that  chosen item was produced by machine B.

let A be the event that the  item is defective .


P( E1 ) = ( 60 / 100 )

P( E2 ) = ( 40/ 100 )

P( A / E1 ) = ( 2 / 100 )

P( A / E2 ) = ( 1 / 100 )


Required probability = P [ item was produced by machine B given that the item was defective ]

Required probability = P [ E2 / A ]






P ( E2 / A ) = [( 40 / 100 )( 1 / 100 )] / { [( 60 / 100 )( 2 / 100 )] + [( 40 / 100 )( 1 / 100 )] }


P ( E2 / A ) =  [40] / {[120]+[40]} =  ( 1 / 4 )
index of more problems on baye's theorem for ncert cbse mathematics
problem 9

Two groups are competing for the position on the Board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. Further, if the first group wins, the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins. Find the probability that the new product introduced was by the second group.

Let E1 be the event that the first group wins .

let E2 be the event that the second group wins.

let A be the event that the  new product was introduced .


P( E1 ) = ( 0.6 )

P( E2 ) = ( 0.4 )

P( A / E1 ) = ( 0.7 )

P( A / E2 ) = ( 0.3 )


Required probability = P [ second group had won given that the new product was introduced ]

Required probability = P [ E2 / A ]


 
  



P ( E2 / A ) = [( 0.4 )( 0.3)] / { [( 0.6 )( 0.7 )] + [( 0.4 )( 0.3 )] }


P ( E2 / A ) =  [0.12] / {[0.42]+[0.12]} =  ( 12 / 54 ) = ( 2 / 9 )


index of more problems on baye's theorem for ncert cbse mathematics

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problem 6 and problem 7 of bayes theorem

There are three coins. One is a two headed coin (having head on both faces),another is a biased coin that comes up heads 75% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows heads, what is the probability that it was the two headed coin ?


Let E1 be the event that the selected coin is the two headed coin .

let E2 be the event that the selected coin is the biased coin that comes up heads 75% of the time.

let E3 be the event that the selected coin is the unbiased coin.

let A be the event that the  toss of the selected coin resulted in a head.

Assuming E1 , E2 , E3 are equally likely

P( E1 ) = ( 1 / 3 )

P( E2 ) = ( 1 / 3 )

P( E3 ) = ( 1 / 3 )

P( A / E1 ) = 1 { since the coin is two headed  in the event of E1 }

P( A / E2 ) = ( 75 / 100 ) = ( 3/4 )  { since the biased coin comes up heads 75% of the time in E2 }

P( A / E3 ) = ( 1 / 2 )  { since the  coin is unbiased in E3 }

Required probability = P [ a person that the two headed coin was selected given that the toss resulted in a head ]

Required probability = P [ E1 / A ]


              



P ( E1 / A ) = [ ( 1 / 3 )( 1 )] / { [( 1 / 3 )( 1 )] + [( 1 / 3 )( 3/4 ) ] + [( 1 / 3 )( 1/2 ) ] }


P ( E1 / A ) =  [1] / { [1]+[3/4]+[1/2] } =  ( 4 /9 )

index of more problems on baye's theorem for ncert cbse mathematics

problem 7

An insurance company insured 2000 scooter drivers, 4000 car drivers and 6000 truck drivers. The probability of an accidents are 0.01, 0.03 and 0.15 respectively. One of the insured persons meets with an accident. What is the probability that he is a scooter driver?

Let E1 be the event that the person is a scooter driver .

let E2 be the event that  the person is a car driver.

let E3 be the event that the person is a truck driver.

let A be the event that the  person met with an accident.

total number of vehicles = 2000 + 4000 + 6000 = 12000

P( E1 ) = ( 2000 / 12000 )

P( E2 ) = ( 4000 / 12000 )

P( E3 ) = ( 6000 / 12000 )

P( A / E1 ) = 0.01

P( A / E2 ) = 0.03

P( A / E3 ) = 0.15

Required probability = P [ person is a scooter driver given that the person met with an accident ]

Required probability = P [ E1 / A ]


         


P ( E1 / A ) = [(2000 / 12000 ) ( 0.01 )] / { [(2000 / 12000) (0.01)] + [(4000 / 12000) (0.03)] + [(6000 / 12000) (0.15)] }


P ( E1 / A ) =  [20] / { [20]+[120]+[900] } =  ( 20 / 1040 ) = ( 1 / 52 )

index of more problems on baye's theorem for ncert cbse mathematics

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problem 4 and 5 of bayes theorem

problem 4

In answering a question on a multiple choice test, a student either knows the answer or guesses. Let ( 3/4 ) be the probability that he knows the answer and ( 1/4) be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability ( 1/4 ). What is the probability that the student knows the answer given that he answered it correctly?


Let E1 be the event that the  student knows the answer.

let E2 be the event that the student guesses the answer.

let A be the event that the answer is correct.

P( E1 ) = ( 3 / 4 )

P( E2 ) = ( 1 / 4 )

P( A / E1 ) = 1 [ E1  means student knows the answer and hence the answer will be correct ]

P( A / E2 ) = ( 1 / 4 )  [ given in the question  ]

Required probability = P [ student knows the answer given that he answered it correctly ]

Required probability = P [ E1 / A ]


 


P ( E1 / A ) = [ ( 3 / 4 )( 1 )] / { [ ( 3 / 4 )( 1 ) ] + [ ( 1 / 4 )( 1 / 4 ) ] }


P ( E1 / A ) =  [3] / { 3 + ( 1/4 )} =  ( 12 / 13 )

index of more problems on baye's theorem for ncert cbse mathematics


problem 5

A laboratory blood test is 99% effective in detecting a certain disease when it is in fact, present. However, the test also yields a false positive result for 0.5% of the healthy person tested (i.e. if a healthy person is tested, then, with probability 0.005, the test will imply he has the disease). If 0.1 percent of the population actually has the disease, what is the probability that a person has the disease given that his test result is positive ?


Let E1 be the event that the person has the disease .

let E2 be the event that the person does not have the disease.

let A be the event that the test result of the person is positive.

P( E1 ) = ( 0.1 / 100 ) [0.1 percent of the population actually has the disease]

P( E2 ) = ( 99.9 / 100 ) [ complement, 100 - 0.1 = 99.9 % of the population does not have the disease ]

P( A / E1 ) = ( 99 / 100 ) [ test is 99% effective in detecting a certain disease when it is in fact, present ]

P( A / E2 ) = ( 0.5 / 100 )  [ the test also yields a false positive result for 0.5% of the healthy person tested ]

Required probability = P [ a person has the disease given that his test result is positive ]

Required probability = P [ E1 / A ]





P ( E1 / A ) = [ ( 0.1 / 100 )( 99 / 100 )] / { [( 0.1 / 100 )( 99 / 100 )] + [ ( 99.9 / 100 )( 0.5 / 100 ) ] }


P ( E1 / A ) =  [ 9.9 ] / { 9.9 + 49.95 } =  ( 9.9 / 59.85 ) = ( 990 / 5985) = ( 22 / 133 )


index of more problems on baye's theorem for ncert cbse mathematics

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bayes theorem problem 2 and 3


A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag.

Let E1 be the event that the first bag is selected.

let E2 be the event that the second bag is selected.

let A be the event of drawing a red ball from the selected bag.

We can assume that E1 and E2 are equally likely so that

P( E1 ) = 1 / 2

P( E2 ) = 1 / 2

P( A / E1 ) = 4 / ( 4 + 4 )  = 4 / 8 [ 4 red balls out of a total of 4 + 4 = 8 balls in the first bag ]

P( A / E2 ) = 2 / ( 2 + 6 ) = 2 / 8  [ 2 red balls out of a total of 2 + 6 = 8 balls  in the second bag]

By bayes theorem ,

 probability that the ball is drawn from the first bag = P ( E1 / A )

                         
               



P ( E1 / A ) =  { (1/2)(4/8) } / { (1/2)(4/8) + (1/2)(2/8) }


P ( E1 / A ) = 4 / 6 =  2 / 3

index of more problems on baye's theorem for ncert cbse mathematics


problem 3

Of the students in a college, it is known that 60% reside in hostel and 40% are day scholars (not residing in hostel). Previous year results report that 30% of all students who reside in hostel attain A grade and 20% of day scholars attain A grade in their annual examination. At the end of the year, one student is chosen at random from the college and he has an A grade, what is the probability that the student is a hostelier?


Let E1 be the event that the chosen student is a hostelier.

let E2 be the event that the chosen student is a day scholar.

let A be the event that the chosen student has a A grade in the annual exam.

P( E1 ) = 60 / 100

P( E2 ) = 40 / 100

P( A / E1 ) = 30 / 100 [ Previous year results report that 30% of all students who reside in hostel attain A grade ]

P( A / E2 ) = 20 / 100  [ Previous year results report that 20% of day scholars attain A grade  ]

Required probability = P [ chosen student is a hostelier given that he has an A grade ]

Required probability = P [ E1 / A ]

  



P ( E1 / A ) = [ (60 / 100 ) ( 30 / 100 )] / { [ (60 / 100 ) ( 30 / 100 ) ] + [ (40 / 100 ) ( 20 / 100 ) ] }


P ( E1 / A ) = ( 18 / { 18 + 8 } ) =  ( 18 / 26 ) = ( 9 / 13 )

index of more problems on baye's theorem for ncert cbse mathematics

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bayes theorem is a topic for cbse / ncert  / scert of 12th standard in India. These are some of the important questions and their solutions from the topic of bayes theorem from various cbse ncert textbooks and old question papers.

bayes theorem of probability

total probability

bayes theorem of probability

Let E1, E2, . . . En be a partition of the sample space S, where E1, E2, . . . En are pairwise disjoint , non empty events.Let A be an event of non zero probability then

total probability



problem 1

An urn contains 5 red and 5 black balls. A ball is drawn at random, its colour is noted and is returned to the urn. Moreover, 2 additional balls of the colour drawn are put in the urn and then a ball is drawn at random. What is theprobability that the second ball is red?

Let E1 be the event that the ball taken out from the first 10 balls is red

let E2 be the event that the ball taken out from the first 10 balls is black.

Let A be the event that the ball taken out from the 12 balls ( after addition of 2 more balls ) is red.

If E1 occurs, then two more red balls will be added to make up seven red balls and five black balls with a total of twelve balls.

If E2 occurs, then two more black balls will be added to make up five red balls and seven black balls with a total of twelve balls.


P( E1 ) = 5 / 10

P( E2 ) = 5 / 10

P( A / E1 ) = 7 / 12 ( if red ball was drawn out first, two more red balls will be added to give 5+2 =7 red balls )

P( A / E2 ) = 5 / 12 ( if black ball was drawn out first, two more black balls will be added and number of red balls will not increase )


P(A) = P( E1 )  P( A / E1 )  +  P( E2 ) P( A / E2 ) ( total probablity )

P(A) = [ 5 / 10 ] [ 7 / 12 ]  +  [ 5 / 10 ] [ 5 / 12 ]

P(A) =  [ 60 / 120 ] =  ( 1 / 2 )




problem 2
A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag.

solution to problem 2 of  bayes theorem

problem 3
Of the students in a college, it is known that 60% reside in hostel and 40% are day scholars (not residing in hostel). Previous year results report that 30% of all students who reside in hostel attain A grade and 20% of day scholars attain A grade in their annual examination. At the end of the year, one student is chosen at random from the college and he has an A grade, what is the probability that the student is a hostelier?

solution to problem 3 of  bayes theorem


problem 4
In answering a question on a multiple choice test, a student either knows the answer or guesses. Let ( 3/4 ) be the probability that he knows the answer and ( 1/4) be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability ( 1/4 ). What is the probability that the student knows the answer given that he answered it correctly?
solution to bayes theorem problem 4 for ncert cbse 12th mathematics

problem 5

A laboratory blood test is 99% effective in detecting a certain disease when it is in fact, present. However, the test also yields a false positive result for 0.5% of the healthy person tested (i.e. if a healthy person is tested, then, with probability 0.005, the test will imply he has the disease). If 0.1 percent of the population actually has the disease, what is the probability that a person has the disease given that his test result is positive ?
solution to bayes theorem problem 5 for ncert cbse 12th mathematics

problem 6

There are three coins. One is a two headed coin (having head on both faces),another is a biased coin that comes up heads 75% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows heads, what is the probability that it was the two headed coin ?

solution to problem 6 of bayes theorem for cbse ncert mathematics

problem 7

An insurance company insured 2000 scooter drivers, 4000 car drivers and 6000 truck drivers. The probability of an accidents are 0.01, 0.03 and 0.15 respectively. One of the insured persons meets with an accident. What is the probability that he is a scooter driver?

solution to problem 7 of bayes theorem for cbse ncert mathematics 

problem 8
 A factory has two machines A and B. Past record shows that machine A produced 60% of the items of output and machine B produced 40% of the items. Further,2% of the items produced by machine A and 1% produced by machine B were defective. All the items are put into one stockpile and then one item is chosen at random from this and is found to be defective. What is the probability that it was produced by machine B?
solution of problem 8 on bayes theorem for cbse mathematics 

problem 9
Two groups are competing for the position on the Board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. Further, if the first group wins, the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins. Find the probability that the new product introduced was by the second group.
solution of problem 9 on bayes theorem for cbse mathematics

problem 10
Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4, she tosses a coin once and notes whether a head or tail is obtained. If she obtained exactly one head, what is the probability that she threw 1, 2, 3 or 4 with the die?
solution of problem10 on bayes theorem for ncert cbse mathematics

problem 11
A manufacturer has three machine operators A, B and C. The first operator A produces 1% defective items, where as the other two operators B and C produce 5% and 7% defective items respectively. A is on the job for 50% of the time, B is on the job for 30% of the time and C is on the job for 20% of the time. A defective item is produced, what is the probability that it was produced by A?
solution of problem11 on bayes theorem for ncert cbse mathematics

problem 12
A card from a pack of 52 cards is lost. From the remaining cards of the pack,two cards are drawn and are found to be both diamonds. Find the probability of the lost card being a diamond.
 solution to bayes theorem problem 12 for ncert cbse mathematics probability

problem 13
Probability that a man speaks truth is (  4 / 5 ). A coin is tossed and the man reports that a head appeared.Find the probability that actually there was a head.
 solution to bayes theorem problem 13for ncert cbse mathematics probability


miscellaneous exercise problem 14
Assume that the chances of a patient having a heart attack is 40%. It is also assumed that a meditation and yoga course reduce the risk of heart attack by 30% and prescription of a certain drug reduces its chances by 25%. At a time a patient can choose any one of the two options with equal probabilities. It is given that after going through one of the two options the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation and yoga?
solution to miscellaneous exercise problem 14 on bayes theorem in  ncert cbse 12th mathematics

miscellaneous exercise problem 15
Bag I contains 3 red and 4 black balls and Bag II contains 4 red and 5 black balls.One ball is transferred from Bag I to Bag II and then a ball is drawn from Bag II. The ball so drawn is found to be red in colour. Find the probability that the transferred ball is black.
solution to miscellaneous exercise problem 15on bayes theorem in  ncert cbse 12th mathematics


disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work


bayes theorem is a topic for cbse / ncert  / scert of 12th standard in India. These are some of the important questions from the topic of bayes theorem from various cbse ncert textbooks and old question papers.