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Showing posts with label integral calculus. Show all posts
Showing posts with label integral calculus. Show all posts

Monday, March 11, 2013

integral using manipulation of numerator in terms of denominator

integral of 1/[sin²x cos²x]

 since sin²x + cos²x =1
 rewrite the numerator as sin²x + cos²x
 divide each term with the denominator
simplify and then integrate

 study  integration formulae






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integral using substitution

integral of [√(tanx)] / [sinx cosx]

first introduce [√(tanx)] in the numerator and denominator

then simplify and change the tanx in the numerator in terms of sinx and cosx
simplify in terms of secx and tanx

then use substitution method

study  integration formulae  







 

free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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Saturday, March 9, 2013

integral using trigonometric manipulation

integral of 1 / [cos(x-a)cos(x-b)]

we will try to write the numerator in terms of the denominator

so introduce sin(a-b) in the numerator and denominator

note that (x-b)-(x-a) =a-b

so write sin(a-b) as sin[ (x-b)-(x-a) ] and expand using sin[A-B] formula

divide the numerator term by term with the denominator

reduce to terms involving sec and then integrate

study  integration formulae a 







 

free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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integral 5

integral of 1 / [x - √x ]

we have to use substitution method

take √x common in the denominator

put √x =t
study differentiation formulae ands  integration formulae
then take the differential

 (1/[2√x] ) dx = dt

rearrange the integral and rewrite it in terms of t in a single step
and then integrate

note that log x stands for natural logarithm ln x in this question






free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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integral 4

integral of (log x )² / x
note that log x stands for natural logarithm ln x in this question

since there is no quotient rule in integration and since this is not a standard form you have to try to use substitution method to get to a standard form


so you put log x =t then take the differential

so (1/x) dx = dt

after that arrange the integral so that you can rewrite the integral in terms of t in a single step

then you get a standard integral which can be integrated.
study  integration formulae





free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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integral 3

integral of sec²x/cosec²x

since there is no quotient rule in integration, change everything in terms of sinx and  cosx simplify to get tan²x
since there is no direct integral for  tan²x change to sec²x-1 using trigonometry formulae and then integrate term by term.
study  integration formulae
and

trigonometry identities formulae etc





free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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integral 2

integral of [ x^3 - x^2 + x -1] / (x-1)

factorise the numerator

cancel off the common factor

use the integral of x^n to integrate term by term
go through the  integration formulae 







free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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index of math problems





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Friday, March 8, 2013

integral1




integral of (x^3 +3x +4) /sqrt(x)

since quotient rule is not used in integration you divide each term in the numerator with the denominator and
reduce every thing to x^n form and then integrate term by term
go through the  integration formulae 










free guide on integration  or integral calculus for cbse isc kerala higher secondary class 12 ncert scert students


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Find p If Two Lines Are Perpendicular | 3D Geometry Solution

 If the lines (x - 3)/1 = (1 - y)/1 = (z + 2)/p and (2 - x)/3 = (y + 1)/5 = (z + 56)/2p are perpendicular to each other, then find the value...