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Showing posts with label to find the equation of a polynomial whose zeroes are given. Show all posts
Showing posts with label to find the equation of a polynomial whose zeroes are given. Show all posts

Thursday, June 25, 2026

While playing badminton Ravi has set the barrier chain hung between two posts at the edge of the walkway of a street. It is hung in the shape of a parabola. Based on the above information answer the following questions : (a) Which type of the polynomial (linear, quadratic, cubic etc.) is graphically represented by a parabola ? (b) If the polynomial represented by a parabola, intersects the x-axis at −2 and 3 and y-axis at −3, then write the zeroes of the parabola. (c) Find the expression for the above polynomial. OR (c) If the zeroes of the polynomial are −5 and 3, find its expression.

 While playing badminton Ravi has set the barrier chain hung between two posts at the edge of the walkway of a street. It is hung in the shape of a parabola.

Based on the above information answer the following questions :

(a) Which type of the polynomial (linear, quadratic, cubic etc.) is graphically represented by a parabola ?

(b) If the polynomial represented by a parabola, intersects the x-axis at −2 and 3 and y-axis at −3, then write the zeroes of the parabola.

(c) Find the expression for the above polynomial.

(d) If the zeroes of the polynomial are −5 and 3, find its expression.


[a] A parabola is the graph of a quadratic polynomial

Given

parabola, intersects the x-axis at −2 and 3 

therefore zeroes are [-2] and 3


Polynomial with roots α and β is given by

f(x) = k(x − α)(x − β)

or

f(x) = k[x² − (α + β)x + αβ]


where k ≠ 0 is any real number.


given that zeroes are [-2] and 3


Take them as

α = [-2]

β = 3

 f(x) = k(x + 2)(x − 3)

use distribution law

f(x) =k(x² − x − 6)


to find k use the condition that parabola cuts y-axis at −3

which means it passes through (0,-3)

so Use f(0) = −3 

k[0-0-6] = [-3]

we get k =(1/2)

and  f(x) = (1/2)(x² − x − 6)


in the last part the zeroes are given to be  −5 and 3

so g(x) = k(x + 5)(x − 3) =kx² + 2x − 15


choose k=1

g(x)  = x² + 2x − 15

see this video for more details 



cbse 10th maths old board exam question papers 2025 2026 to find the equation of a polynomial whose zeroes are given


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