integral of e^(2-3x) with limit 0 to 1 using limit of sums
identify a =0 , b=1
nh = b-a = 1
f(x) = e^(2-3x)
find f(a) = f(0)
f(a+h)=f(h)
f(a+2h) = f[2h]
till the pattern can be identified,
f(a + (n-1) h ) = f[(n-1) h] etc
simplify using properties of sum of n terms of a GP.
and use the limit [(e^h) -1] / h tends to 1 as h tends to 0
formulae on integration
PAGE 1 BASIC INTEGRATION
PAGE 2 INTEGRATION BY SUBSTITUTION
PAGE 3 INTEGRATION BY COMPLETION OF SQUARES
PAGE 4 INTEGRATION BY PARTS
PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR
PAGE 6 INTEGRATION USING PARTIAL FRACTIONS
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Showing posts with label chapter 7 miscellaneous. Show all posts
Showing posts with label chapter 7 miscellaneous. Show all posts
Tuesday, January 24, 2017
Friday, January 20, 2017
integral of { (cosx)^2 / [ (cosx)^2+ 4 (sinx)^2 ] }
integral of { (cos x)^2 / [ (cos x)^2+ 4 (sin x)^2 ] }
use trigonometric formulae to change (sin x)^2 = 1 - (cos x)^2 so that the intergral is completely in terms of (cos x)^2 .
Now try to write the numerator in terms of the denominator.
introduce a (-3 ) in the numerator and denominator and add and subtract 4
split it into two terms and then two integrals
The second integral contains (cos x)^2 .
divide each term with (cos x)^2 to get (sec x)^2
use trigonometric formulae tochange (sec x)^2 = 1+ (tan x)^2 in the denominator only
use substitution t = tan x and change the limits.
formulae on integration
PAGE 1 BASIC INTEGRATION
PAGE 2 INTEGRATION BY SUBSTITUTION
PAGE 3 INTEGRATION BY COMPLETION OF SQUARES
PAGE 4 INTEGRATION BY PARTS
PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR
PAGE 6 INTEGRATION USING PARTIAL FRACTIONS
disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work
use trigonometric formulae to change (sin x)^2 = 1 - (cos x)^2 so that the intergral is completely in terms of (cos x)^2 .
Now try to write the numerator in terms of the denominator.
introduce a (-3 ) in the numerator and denominator and add and subtract 4
split it into two terms and then two integrals
The second integral contains (cos x)^2 .
divide each term with (cos x)^2 to get (sec x)^2
use trigonometric formulae tochange (sec x)^2 = 1+ (tan x)^2 in the denominator only
use substitution t = tan x and change the limits.
formulae on integration
PAGE 1 BASIC INTEGRATION
PAGE 2 INTEGRATION BY SUBSTITUTION
PAGE 3 INTEGRATION BY COMPLETION OF SQUARES
PAGE 4 INTEGRATION BY PARTS
PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR
PAGE 6 INTEGRATION USING PARTIAL FRACTIONS
disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work
Wednesday, January 18, 2017
integral of 1 / [cos(x+a)cos(x+b)]
integral of 1 / [cos(x+a)cos(x+b)] by manipulating the angle in the numerator in terms of the angles of the denominator
introduce a term sin(a-b) in the numerator by multiplying the numerator and denominator with it.
Then express the angle (a-b) in terms of the denominator(x+a) and (x+b)
using (a-b) = (x+a) - (x+b)
use trigonometric formula for expanding the numerator and then split the numerator
then simplify and integrate the two terms separately.
PAGE 1 BASIC INTEGRATION
PAGE 2 INTEGRATION BY SUBSTITUTION
PAGE 3 INTEGRATION BY COMPLETION OF SQUARES
PAGE 4 INTEGRATION BY PARTS
PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR
PAGE 6 INTEGRATION USING PARTIAL FRACTIONS
disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work
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