integral of cosx / [ 1- cos²x]

using 1- cos²x = sin²x

∫ { cosx / [ 1- cos²x] } dx = ∫ { cosx / [sin²x] } dx

= ∫ {1 / sin x} {cos x / sin x} dx

= ∫ cosec x cot x dx

= - cosec x + c


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