linear differential equation y dx + [x-(y^2)]dy = 0

linear differential equation from ncert cbse

solve y dx + [x-(y^2)]dy = 0

The equation contains only one x term

Therefore try to solve for [dx/dy] and compare with the linear differential equation of the form

[dx/dy] + Px = Q

Then compare and get the values of P and Q

find the integrating factor of the linear differential equation using the formula

I.F. = e^[integral of P dx]

use the property e^[ln[f(y)] = f(y)

then use the solution

x[I.F.] = integral of [ Q * I.F.]dy +C

Variable separable differential equation

*find the equation of the curve passing through (0,pi/4) whose differential equation is
sinx cosy dx +  cosx siny dy =0
solution of  variable separable differential equation find the equation of the curve passing through (0,pi/4) whose differential equation issinx cosy dx +  cosx siny dy =0

* show that the general solution of y' + {[ (y^2)+y + 1]/[x^2+x+1] = 0
is given by x+y+1=A[1-x-y-2xy]

solution of variable separable differential equation from ncert cbse miscellaneous problem

*solve y e^(x/y) = [ y e^(x/y) + (y^2) ]dy  [ y is not equal to 0]
solution of differential equation which is not homogeneous but which can be solved using x=vy

*linear differential equation 

solve [ { e^[-2sqrt(x)] / sqrt(x) } - {y / sqrt(x)}] [dx/dy] = 1  [x is not 0]
solution of linear differential equation of ncert cbse miscellaneous differential equation

*linear differential equation of the type
solve y dx + [x-(y^2)]dy = 0
solution of linear differential equation of the type [dx/dy] + Px = Q


*find a particular solution of the differential equation [dy/dx]+ycotx =4xcosecx [x is not 0] given that y =0 if x=pi/2
solution of linear differential equation from ncert cbse miscellaneous  [dy/dx]+ycotx =4xcosecx [x is not 0] given that y =0 if x=pi/2

solution of a second order differential equation using reduction of order
solve y"-y = 0 if y = coshx is one of the solutions
using the formula for reduction of order
solution of solution of a second order differential equation using reduction of order

variation of parameter method

solve xy" - 4y' = x^4 by method of variation of parameter
solution to problem on differential questions using variation of parameter method

orthogonal trajectory of y(1+x ² ) = Cx

find the orthogonal trajectory of y(1+x ² ) = Cx
answer to problem on  orthogonal trajectory of y(1+x ² ) = Cx

orthogonal trajectory of y = (k/x)

find the orthogonal trajectory of y = (k/x)
solution to  find the orthogonal trajectory of y = (k/x)



formulae on integration
 
PAGE 1 BASIC INTEGRATION

PAGE 2 INTEGRATION BY SUBSTITUTION

 PAGE 3 INTEGRATION BY COMPLETION OF SQUARES

PAGE 4 INTEGRATION BY PARTS

PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR


PAGE 6 INTEGRATION USING PARTIAL FRACTIONS

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There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work

linear differential equation

linear differential equation  from ncert cbse miscellaneous differential equation

find a particular solution of the differential equation [dy/dx]+ycotx =4xcosecx [x is not 0] given that y =0 if x=pi/2

the equation is an example of linear differential equation, so compare [dy/dx]+ycotx =4xcosecx with the standard linear differential equation [dy/dx]+Pycotx =Q

Identify the values of P and Q

here P=cotx

Q=4xcosecx

Find the integrating factor[I.F.]  = e^[integral of P ]

use the result e^[ln{f(x)}] = f(x)

use the solution

y[I.F.] = integral of [ Q* I.F. ] +C

Variable separable differential equation

*find the equation of the curve passing through (0,pi/4) whose differential equation is
sinx cosy dx +  cosx siny dy =0
solution of  variable separable differential equation find the equation of the curve passing through (0,pi/4) whose differential equation issinx cosy dx +  cosx siny dy =0

* show that the general solution of y' + {[ (y^2)+y + 1]/[x^2+x+1] = 0
is given by x+y+1=A[1-x-y-2xy]

solution of variable separable differential equation from ncert cbse miscellaneous problem

*solve y e^(x/y) = [ y e^(x/y) + (y^2) ]dy  [ y is not equal to 0]
solution of differential equation which is not homogeneous but which can be solved using x=vy

*linear differential equation 

solve [ { e^[-2sqrt(x)] / sqrt(x) } - {y / sqrt(x)}] [dx/dy] = 1  [x is not 0]
solution of linear differential equation of ncert cbse miscellaneous differential equation


solution of a second order differential equation using reduction of order
solve y"-y = 0 if y = coshx is one of the solutions
using the formula for reduction of order
solution of solution of a second order differential equation using reduction of order

variation of parameter method

solve xy" - 4y' = x^4 by method of variation of parameter
solution to problem on differential questions using variation of parameter method

orthogonal trajectory of y(1+x ² ) = Cx

find the orthogonal trajectory of y(1+x ² ) = Cx
answer to problem on  orthogonal trajectory of y(1+x ² ) = Cx

orthogonal trajectory of y = (k/x)

find the orthogonal trajectory of y = (k/x)
solution to  find the orthogonal trajectory of y = (k/x)



formulae on integration
 
PAGE 1 BASIC INTEGRATION

PAGE 2 INTEGRATION BY SUBSTITUTION

 PAGE 3 INTEGRATION BY COMPLETION OF SQUARES

PAGE 4 INTEGRATION BY PARTS

PAGE 5 INTEGRATION BY MANIPULATION OF NUMERATOR IN TERMS OF DENOMINATOR


PAGE 6 INTEGRATION USING PARTIAL FRACTIONS

disclaimer:
There is no guarantee about the data/information on this site. You use the data/information at your own risk. You use the advertisements displayed on this page at your own risk.We are not responsible for the content of external internet sites. Some of the links may not work