to find cot(x ) if you are given that sin(x)=2/3 by drawing a triangle

find cot(x ) if you are given that sin(x)=2/3 and that x is acute.

draw a rt. triangle with one angle as x (not the right angle)



choose the opp. side as 2 and hypotenuse as 3 so that the third side is
sqrt(5) (using pythagoras theorem)

so cot(x) = (sqrt 5) /2


some trigonometry formulae

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