๐๐ผ๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ๐จ ๐๐ช๐๐๐
๐๐ง๐ค๐ฌ๐ฉ๐, ๐ฟ๐๐๐๐ฎ, ๐๐๐ง๐๐๐ฃ๐ฉ๐๐๐๐จ, ๐๐ง๐๐ฅ๐๐จ, ๐๐๐๐ก๐๐จ ๐๐ฃ๐ ๐๐ค๐ง๐ ๐๐ง๐ค๐๐ก๐๐ข๐จ
An exponential function can look complicated at first.
But underneath the equation, table, graph or word problem, there is usually one simple idea:
๐๐๐ ๐จ๐๐ข๐ ๐ข๐ช๐ก๐ฉ๐๐ฅ๐ก๐๐๐ง ๐๐จ ๐๐ฅ๐ฅ๐ก๐๐๐ ๐๐๐๐๐ฃ ๐๐ฃ๐ ๐๐๐๐๐ฃ.
That single idea connects exponential equations, exponential growth, exponential decay, percentage changes, doubling, halving, tables and graphs.
This guide brings those ideas together in one place.
✦ ๐ญ. ๐๐๐๐ฉ ๐๐จ ๐ผ๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ?
A common exponential function is written as:
๐(๐) = ๐(๐หฃ)
There are three important parts.
๐ = starting value
๐ = multiplication factor
๐ = number of repeated changes
The most important clue is that the variable appears in the exponent.
For example:
๐(๐) = ๐ฑ(๐ฎหฃ)
is exponential because ๐ is in the exponent.
But:
๐(๐) = ๐ฑ๐²
is not an exponential function.
Here, the variable is the base and the exponent is fixed.
✦ ๐ฎ. ๐๐๐ ๐๐๐๐ฃ ๐๐๐a: ๐ผ๐๐ ๐๐ง ๐๐ช๐ก๐ฉ๐๐ฅ๐ก๐ฎ?
This is one of the quickest ways to distinguish linear and exponential patterns.
Consider:
๐ฏ, ๐ฒ, ๐ต, ๐ญ๐ฎ, ๐ญ๐ฑ
The same amount is added each time:
+๐ฏ
This is a linear pattern.
Now consider:
๐ฏ, ๐ฒ, ๐ญ๐ฎ, ๐ฎ๐ฐ, ๐ฐ๐ด
Each value is multiplied by:
×๐ฎ
This is an exponential pattern.
๐๐๐ข๐๐ข๐๐๐ง:
๐๐๐ข๐ ๐๐๐๐๐๐ง๐๐ฃ๐๐ → ๐ก๐๐ฃ๐๐๐ง
๐๐๐ข๐ ๐ง๐๐ฉ๐๐ค → ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก
✦ ๐ฏ. ๐๐๐๐ฉ ๐ฟ๐ค๐๐จ ๐ ๐๐๐๐ฃ?
Look at:
๐(๐) = ๐ด(๐ฏหฃ)
The starting value is:
๐ = ๐ด
Why?
Set:
๐ = ๐ฌ
Then:
๐(๐ฌ) = ๐ด(๐ฏ⁰)
Since:
๐ฏ⁰ = ๐ญ
we get:
๐(๐ฌ) = ๐ด
So in:
๐(๐) = ๐(๐หฃ)
the value of ๐ is the output when ๐ = ๐ฌ.
✦ ๐ฐ. ๐๐๐๐ฉ ๐ฟ๐ค๐๐จ ๐ ๐๐๐๐ฃ?
In:
๐(๐) = ๐(๐หฃ)
the number ๐ tells you how the output changes when ๐ increases by 1.
For example:
๐(๐) = ๐ฑ(๐ฎหฃ)
Values include:
๐(๐ฌ) = ๐ฑ
๐(๐ญ) = ๐ญ๐ฌ
๐(๐ฎ) = ๐ฎ๐ฌ
๐(๐ฏ) = ๐ฐ๐ฌ
Every step multiplies the previous value by:
×๐ฎ
So the base is the repeated multiplier.
✦ ๐ฑ. ๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐๐ง๐จ๐ช๐จ ๐ฟ๐๐๐๐ฎ
The base gives you an immediate clue.
๐๐ ๐ > ๐ญ:
The function shows exponential growth.
Example:
๐(๐) = ๐ญ๐ฌ(๐ญ.๐ฎหฃ)
๐๐ ๐ฌ < ๐ < ๐ญ:
The function shows exponential decay.
Example:
๐(๐) = ๐ญ๐ฌ(๐ฌ.๐ดหฃ)
The values get smaller as ๐ increases.
๐๐ช๐๐๐ ๐๐๐๐๐ :
๐ > ๐ญ → ๐๐ง๐ค๐ฌ๐ฉ๐
๐ฌ < ๐ < ๐ญ → ๐ฟ๐๐๐๐ฎ
✦ ๐ฒ. ๐๐ช๐ง๐ฃ๐๐ฃ๐ ๐๐๐ง๐๐๐ฃ๐ฉ๐๐๐๐จ ๐๐ฃ๐ฉ๐ค ๐๐ช๐ก๐ฉ๐๐ฅ๐ก๐๐๐ง๐จ
This is one of the most important skills in exponential word problems.
Suppose something increases by ๐ญ๐ฌ%.
A 10% increase means the new amount is:
๐ญ๐ฌ๐ฌ% + ๐ญ๐ฌ% = ๐ญ๐ญ๐ฌ%
As a decimal:
๐ญ.๐ญ๐ฌ
Therefore:
๐ญ๐ฌ% ๐๐ฃ๐๐ง๐๐๐จ๐ → ×๐ญ.๐ญ๐ฌ
Suppose something increases by ๐ฎ๐ฑ%.
๐ญ๐ฌ๐ฌ% + ๐ฎ๐ฑ% = ๐ญ๐ฎ๐ฑ%
Therefore:
๐ฎ๐ฑ% ๐๐ฃ๐๐ง๐๐๐จ๐ → ×๐ญ.๐ฎ๐ฑ
✦ ๐ณ. ๐๐๐ง๐๐๐ฃ๐ฉ๐๐๐ ๐ฟ๐๐๐ง๐๐๐จ๐๐จ
Suppose something decreases by ๐ญ๐ฌ%.
The amount remaining is:
๐ญ๐ฌ๐ฌ% − ๐ญ๐ฌ% = ๐ต๐ฌ%
As a decimal:
๐ฌ.๐ต๐ฌ
Therefore:
๐ญ๐ฌ% ๐๐๐๐ง๐๐๐จ๐ → ×๐ฌ.๐ต๐ฌ
Similarly:
๐ฎ๐ฌ% decrease → ×๐ฌ.๐ด๐ฌ
๐ฏ๐ฌ% decrease → ×๐ฌ.๐ณ๐ฌ
๐ฐ๐ฌ% decrease → ×๐ฌ.๐ฒ๐ฌ
๐ฑ๐ฌ% decrease → ×๐ฌ.๐ฑ๐ฌ
⚠️ ✦ ๐ด. ๐๐๐ ๐ฝ๐๐ ๐๐๐ง๐๐๐ฃ๐ฉ๐๐๐ ๐๐ง๐๐ฅ
Suppose a quantity decreases by ๐ด๐ฌ%.
The incorrect multiplier is:
๐ฌ.๐ด๐ฌ
Why?
Because 80% is the amount removed, not the amount remaining.
The amount remaining is:
๐ญ๐ฌ๐ฌ% − ๐ด๐ฌ% = ๐ฎ๐ฌ%
Therefore:
๐ด๐ฌ% ๐๐๐๐ง๐๐๐จ๐ → ×๐ฌ.๐ฎ๐ฌ
This is an easy place to lose a question.
✦ ๐ต. ๐ฝ๐ช๐๐ก๐๐๐ฃ๐ ๐ผ๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ค๐๐๐ก
Suppose a population begins at:
๐ฎ๐ฌ๐ฌ๐ฌ
and increases by:
๐ฑ% per year
Starting value:
๐ = ๐ฎ๐ฌ๐ฌ๐ฌ
Growth multiplier:
๐ญ + ๐ฌ.๐ฌ๐ฑ = ๐ญ.๐ฌ๐ฑ
Therefore:
๐ท(๐) = ๐ฎ๐ฌ๐ฌ๐ฌ(๐ญ.๐ฌ๐ฑแต)
The structure is always:
๐๐ฉ๐๐ง๐ฉ๐๐ฃ๐ ๐ซ๐๐ก๐ช๐ × (๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐๐๐ฉ๐ค๐ง)แต
✦ ๐ญ๐ฌ. ๐ฟ๐๐๐๐ฎ ๐๐ค๐๐๐ก๐จ
Suppose a machine is worth:
$๐ญ๐ฑ๐ฌ๐ฌ๐ฌ
and loses:
๐ญ๐ฎ% of its value each year
The amount remaining each year is:
๐ญ − ๐ฌ.๐ญ๐ฎ = ๐ฌ.๐ด๐ด
Therefore:
๐ฝ(๐) = ๐ญ๐ฑ๐ฌ๐ฌ๐ฌ(๐ฌ.๐ด๐ดแต)
Notice something important.
The machine does not lose $1,800 every year.
It loses 12% of its current value.
That distinction creates exponential decay.
✦ ๐ญ๐ญ. ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐จ ๐๐๐ฃ๐๐๐ง ๐๐ง๐ค๐ฌ๐ฉ๐
Suppose two quantities start at 100.
๐๐๐ฃ๐๐๐ง
Increase by 20 each time:
๐ญ๐ฌ๐ฌ, ๐ญ๐ฎ๐ฌ, ๐ญ๐ฐ๐ฌ, ๐ญ๐ฒ๐ฌ, ๐ญ๐ด๐ฌ
๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก
Increase by 20% each time:
๐ญ๐ฌ๐ฌ, ๐ญ๐ฎ๐ฌ, ๐ญ๐ฐ๐ฐ, ๐ญ๐ณ๐ฎ.๐ด, ๐ฎ๐ฌ๐ณ.๐ฏ๐ฒ
The first adds the same amount.
The second multiplies by the same factor.
๐๐๐๐ฉ ๐๐จ ๐ฉ๐๐ ๐๐จ๐จ๐จ๐๐ฃ๐ฉ๐๐๐ก ๐๐๐๐๐๐ง๐๐ฃ๐๐.
✦ ๐ญ๐ฎ. ๐๐๐ฃ๐๐๐ฃ๐ ๐๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ ๐๐ง๐ค๐ข ๐ ๐๐๐๐ก๐
Consider:
| ๐ | ๐(๐) |
|---|---|
| ๐ฌ | ๐ฑ |
| ๐ญ | ๐ญ๐ฌ |
| ๐ฎ | ๐ฎ๐ฌ |
| ๐ฏ | ๐ฐ๐ฌ |
| ๐ฐ | ๐ด๐ฌ |
Look at consecutive ratios.
๐ญ๐ฌ ÷ ๐ฑ = ๐ฎ
๐ฎ๐ฌ ÷ ๐ญ๐ฌ = ๐ฎ
๐ฐ๐ฌ ÷ ๐ฎ๐ฌ = ๐ฎ
๐ด๐ฌ ÷ ๐ฐ๐ฌ = ๐ฎ
The multiplier is:
๐ = ๐ฎ
The starting value is:
๐ = ๐ฑ
Therefore:
๐(๐) = ๐ฑ(๐ฎหฃ)
✦ ๐ญ๐ฏ. ๐๐๐ฃ๐๐๐ฃ๐ ๐ ๐๐๐จ๐จ๐๐ฃ๐ ๐๐๐ก๐ช๐
Suppose:
| ๐ | ๐(๐) |
|---|---|
| ๐ฌ | ๐ฒ |
| ๐ญ | ๐ญ๐ด |
| ๐ฎ | ? |
| ๐ฏ | ๐ญ๐ฒ๐ฎ |
The multiplier is:
๐ญ๐ด ÷ ๐ฒ = ๐ฏ
So:
๐ฒ × ๐ฏ = ๐ญ๐ด
๐ญ๐ด × ๐ฏ = ๐ฑ๐ฐ
๐ฑ๐ฐ × ๐ฏ = ๐ญ๐ฒ๐ฎ
Therefore:
๐(๐ฎ) = ๐ฑ๐ฐ
You do not always need to build the entire equation.
Sometimes the pattern is enough.
✦ ๐ญ๐ฐ. ๐ฟ๐ค๐ช๐๐ก๐๐ฃ๐ ๐๐๐ฉ๐ฉ๐๐ง๐ฃ๐จ
Suppose a quantity doubles every 3 hours.
If ๐ represents hours, the model is:
๐จ(๐) = ๐จ₀(๐ฎ)แต⁄³
Why is the exponent ๐⁄๐ฏ?
Because one doubling occurs every 3 hours.
For example, if the starting amount is 100:
After 3 hours:
๐ญ๐ฌ๐ฌ × ๐ฎ = ๐ฎ๐ฌ๐ฌ
After 6 hours:
๐ญ๐ฌ๐ฌ × ๐ฎ² = ๐ฐ๐ฌ๐ฌ
After 9 hours:
๐ญ๐ฌ๐ฌ × ๐ฎ³ = ๐ด๐ฌ๐ฌ
✦ ๐ญ๐ฑ. ๐๐ง๐๐ฅ๐ก๐๐ฃ๐ ๐๐๐ฉ๐ฉ๐๐ง๐ฃ๐จ
If a quantity triples every 4 hours:
๐จ(๐) = ๐จ₀(๐ฏ)แต⁄⁴
If the initial value is 50:
๐จ(๐) = ๐ฑ๐ฌ(๐ฏ)แต⁄⁴
After 4 hours:
๐ฑ๐ฌ × ๐ฏ = ๐ญ๐ฑ๐ฌ
After 8 hours:
๐ฑ๐ฌ × ๐ฏ² = ๐ฐ๐ฑ๐ฌ
✦ ๐ญ๐ฒ. ๐๐๐ก๐-๐๐๐๐ ๐๐๐ฉ๐ฉ๐๐ง๐ฃ๐จ
If a quantity is reduced to half every 5 years:
๐จ(๐) = ๐จ₀(๐ญ⁄๐ฎ)แต⁄⁵
Suppose:
๐จ₀ = ๐ญ๐ฒ๐ฌ
Then:
After 5 years:
๐ญ๐ฒ๐ฌ × ๐ญ⁄๐ฎ = ๐ด๐ฌ
After 10 years:
๐ญ๐ฒ๐ฌ × (๐ญ⁄๐ฎ)² = ๐ฐ๐ฌ
After 15 years:
๐ญ๐ฒ๐ฌ × (๐ญ⁄๐ฎ)³ = ๐ฎ๐ฌ
The quantity keeps being multiplied by the same factor.
✦ ๐ญ๐ณ. ๐๐๐๐ฃ ๐๐๐ ๐๐๐ข๐ ๐๐ฃ๐๐ฉ ๐พ๐๐๐ฃ๐๐๐จ
Be careful when the time unit in the question does not match the time unit in the model.
Suppose a quantity doubles every:
4 years
and ๐ is measured in years.
Then:
๐จ(๐) = ๐จ₀(๐ฎ)แต⁄⁴
But if ๐ represents four-year periods instead, the model could simply be:
๐จ(๐) = ๐จ₀(๐ฎแต)
Always ask:
“๐๐๐๐ฉ ๐๐ค๐๐จ ๐ญ ๐ช๐ฃ๐๐ฉ ๐ค๐ ๐ ๐ง๐๐ฅ๐ง๐๐จ๐๐ฃ๐ฉ?”
That one question can prevent a major modeling error.
✦ ๐ญ๐ด. ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ ๐๐ช๐ก๐๐จ
Exponential functions become much easier when the basic exponent rules are automatic.
๐⁰ = ๐ญ
๐แต × ๐โฟ = ๐แต⁺โฟ
๐แต ÷ ๐โฟ = ๐แต⁻โฟ
(๐แต)โฟ = ๐แตโฟ
๐⁻โฟ = ๐ญ⁄๐โฟ
For example:
๐ฎ³ × ๐ฎ⁴ = ๐ฎ⁷
because:
๐ฏ + ๐ฐ = ๐ณ
⚠️ ✦ ๐ญ๐ต. ๐ฟ๐ค ๐๐ค๐ฉ ๐ผ๐๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐จ ๐๐๐๐ฃ ๐ผ๐๐๐๐ฃ๐
This rule:
๐แต × ๐โฟ = ๐แต⁺โฟ
is for multiplication.
It does not mean:
๐แต + ๐โฟ = ๐แต⁺โฟ
For example:
๐ฎ² + ๐ฎ³
equals:
๐ฐ + ๐ด = ๐ญ๐ฎ
It does not equal:
๐ฎ⁵
Always look at the operation before choosing an exponent rule.
✦ ๐ฎ๐ฌ. ๐๐ค๐ก๐ซ๐๐ฃ๐ ๐๐๐ข๐ฅ๐ก๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ฆ๐ช๐๐ฉ๐๐ค๐ฃ๐จ
Consider:
๐ฎหฃ = ๐ฏ๐ฎ
Rewrite 32 as a power of 2:
๐ฏ๐ฎ = ๐ฎ⁵
Therefore:
๐ฎหฃ = ๐ฎ⁵
So:
๐ = ๐ฑ
The key strategy is:
๐๐ง๐ฎ ๐ฉ๐ค ๐ฌ๐ง๐๐ฉ๐ ๐๐ค๐ฉ๐ ๐จ๐๐๐๐จ ๐ฌ๐๐ฉ๐ ๐ฉ๐๐ ๐จ๐๐ข๐ ๐๐๐จ๐.
✦ ๐ฎ๐ญ. ๐๐ง๐๐ฅ๐๐จ ๐๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ๐จ
For:
๐(๐) = ๐(๐หฃ)
the graph is curved rather than a straight line.
If:
๐ > ๐ญ
the graph rises as ๐ increases.
If:
๐ฌ < ๐ < ๐ญ
the graph falls as ๐ increases.
The graph passes through:
(๐ฌ, ๐)
because:
๐(๐ฌ) = ๐
For the basic form with no vertical shift, the graph approaches:
๐ = ๐ฌ
as the curve extends in the appropriate direction.
✦ ๐ฎ๐ฎ. ๐๐๐๐ฉ ๐ฟ๐ค๐๐จ ๐ ๐ฟ๐ค?
Consider:
๐(๐) = ๐(๐หฃ) + ๐
The +๐ moves the entire graph vertically.
For example:
๐(๐) = ๐ฏ(๐ฎหฃ) + ๐ฑ
has horizontal asymptote:
๐ = ๐ฑ
The vertical shift changes the long-term position of the graph.
✦ ๐ฎ๐ฏ. ๐๐๐ฃ๐๐๐ฃ๐ ๐๐๐ ๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐๐๐ฉ๐ค๐ง
Suppose a quantity changes from:
๐ฎ๐ฌ๐ฌ → ๐ฎ๐ฏ๐ฌ
The multiplier is:
๐ฎ๐ฏ๐ฌ ÷ ๐ฎ๐ฌ๐ฌ = ๐ญ.๐ญ๐ฑ
Therefore the growth factor is:
๐ญ.๐ญ๐ฑ
The percentage increase is:
๐ญ.๐ญ๐ฑ − ๐ญ = ๐ฌ.๐ญ๐ฑ
which is:
๐ญ๐ฑ%
So:
×๐ญ.๐ญ๐ฑ = ๐ญ๐ฑ% growth
✦ ๐ฎ๐ฐ. ๐๐๐ฃ๐๐๐ฃ๐ ๐๐๐ ๐ฟ๐๐๐๐ฎ ๐๐๐ฉ๐
Suppose a quantity changes from:
๐ฑ๐ฌ๐ฌ → ๐ฐ๐ฎ๐ฑ
The multiplier is:
๐ฐ๐ฎ๐ฑ ÷ ๐ฑ๐ฌ๐ฌ = ๐ฌ.๐ด๐ฑ
The amount remaining is:
๐ด๐ฑ%
Therefore the decrease is:
๐ญ๐ฑ%
So:
×๐ฌ.๐ด๐ฑ = ๐ญ๐ฑ% decay
✦ ๐ฎ๐ฑ. ๐๐๐ ๐๐ฃ๐-๐๐ฉ๐๐ฅ ๐๐ช๐ก๐ฉ๐๐ฅ๐ก๐๐๐ง ๐๐ช๐ก๐
For:
๐(๐) = ๐(๐หฃ)
we can write:
๐(๐ + ๐ญ) = ๐๐(๐)
This is powerful because it tells you exactly what happens after one additional step.
Suppose:
๐(๐ + ๐ญ) = ๐ฐ๐(๐)
Then the multiplier is:
๐ = ๐ฐ
If:
๐(๐ฌ) = ๐ฏ
then:
๐(๐ญ) = ๐ญ๐ฎ
๐(๐ฎ) = ๐ฐ๐ด
๐(๐ฏ) = ๐ญ๐ต๐ฎ
✦ ๐ฎ๐ฒ. ๐๐ผ๐ ๐๐ค๐ง๐ ๐๐ง๐ค๐๐ก๐๐ข ๐๐ง๐๐ฃ๐จ๐ก๐๐ฉ๐๐ค๐ฃ
Words such as these should immediately make you think about exponential models:
“increases by ๐ฑ% each year”
→ ×๐ญ.๐ฌ๐ฑ
“decreases by ๐ญ๐ฎ% each month”
→ ×๐ฌ.๐ด๐ด
“doubles every ๐ฏ hours”
→ ×๐ฎ every ๐ฏ hours
“triples every ๐ฑ days”
→ ×๐ฏ every ๐ฑ days
“is reduced by half every ๐ฐ years”
→ ×๐ญ⁄๐ฎ every ๐ฐ years
The wording changes.
The underlying mathematics remains the same.
✦ ๐ฎ๐ณ. ๐๐ค๐ง๐ ๐๐ง๐ค๐๐ก๐๐ข: ๐๐ง๐ค๐ฌ๐ฉ๐
A town has a population of ๐ญ๐ฌ,๐ฌ๐ฌ๐ฌ and grows by ๐ฎ% each year.
Step ๐ญ: Starting value
๐ = ๐ญ๐ฌ๐ฌ๐ฌ๐ฌ
Step ๐ฎ: Growth factor
๐ญ + ๐ฌ.๐ฌ๐ฎ = ๐ญ.๐ฌ๐ฎ
Step ๐ฏ: Build the model
๐ท(๐) = ๐ญ๐ฌ๐ฌ๐ฌ๐ฌ(๐ญ.๐ฌ๐ฎแต)
The equation describes the population after ๐ years.
✦ ๐ฎ๐ด. ๐๐ค๐ง๐ ๐๐ง๐ค๐๐ก๐๐ข: ๐ฟ๐๐๐๐ฎ
A car is worth $๐ฎ๐ฌ,๐ฌ๐ฌ๐ฌ and loses ๐ญ๐ฑ% of its value each year.
Remaining percentage:
๐ญ๐ฌ๐ฌ% − ๐ญ๐ฑ% = ๐ด๐ฑ%
Multiplier:
๐ฌ.๐ด๐ฑ
Therefore:
๐ฝ(๐) = ๐ฎ๐ฌ๐ฌ๐ฌ๐ฌ(๐ฌ.๐ด๐ฑแต)
Notice that the exponent counts the number of years.
✦ ๐ฎ๐ต. ๐๐๐ ๐๐๐ข๐ ๐๐๐ง๐๐๐ฃ๐ฉ๐๐๐ ๐ฟ๐ค๐๐จ ๐๐ค๐ฉ ๐๐๐๐ฃ ๐๐๐ ๐๐๐ข๐ ๐ผ๐ข๐ค๐ช๐ฃ๐ฉ
This is a crucial concept.
Suppose a value is:
๐ญ๐ฌ๐ฌ
and decreases by ๐ญ๐ฌ%.
First decrease:
๐ญ๐ฌ๐ฌ × ๐ฌ.๐ต = ๐ต๐ฌ
Second decrease:
๐ต๐ฌ × ๐ฌ.๐ต = ๐ด๐ญ
Third decrease:
๐ด๐ญ × ๐ฌ.๐ต = ๐ณ๐ฎ.๐ต
The decrease amounts are:
๐ญ๐ฌ
then:
๐ต
then:
๐ด.๐ญ
The percentage remains the same.
The actual amount changes.
That is why the process is exponential.
✦ ๐ฏ๐ฌ. ๐๐๐ฎ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ง๐ค๐ฌ๐ฉ๐ ๐พ๐๐ฃ ๐๐ช๐ง๐ฅ๐๐จ๐จ ๐๐๐ฃ๐๐๐ง ๐๐ง๐ค๐ฌ๐ฉ๐
Imagine:
Linear: add 10 each step.
Exponential: multiply by 1.10 each step.
Starting from 100:
Linear:
๐ญ๐ฌ๐ฌ → ๐ญ๐ญ๐ฌ → ๐ญ๐ฎ๐ฌ → ๐ญ๐ฏ๐ฌ → ๐ญ๐ฐ๐ฌ
Exponential:
๐ญ๐ฌ๐ฌ → ๐ญ๐ญ๐ฌ → ๐ญ๐ฎ๐ญ → ๐ญ๐ฏ๐ฏ.๐ญ → ๐ญ๐ฐ๐ฒ.๐ฐ๐ญ
At first the values look similar.
But repeated multiplication can eventually produce a very large difference.
✦ ๐ฏ๐ญ. ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ง๐ค๐ฌ๐ฉ๐ ๐พ๐๐ฃ ๐ฝ๐ ๐๐๐จ๐ฉ
Consider:
๐(๐) = ๐ฎ(๐ฏหฃ)
The first few values are:
๐ = ๐ฌ → ๐ฎ
๐ = ๐ญ → ๐ฒ
๐ = ๐ฎ → ๐ญ๐ด
๐ = ๐ฏ → ๐ฑ๐ฐ
๐ = ๐ฐ → ๐ญ๐ฒ๐ฎ
Every step multiplies the previous output by 3.
That repeated multiplication is the heart of exponential growth.
✦ ๐ฏ๐ฎ. ๐๐๐ ๐๐ค๐จ๐ฉ ๐พ๐ค๐ข๐ข๐ค๐ฃ ๐๐๐จ๐ฉ๐๐ ๐๐จ
❌ ๐๐๐จ๐ฉ๐๐ ๐ ๐ญ: ๐๐จ๐๐ฃ๐ ๐ฌ.๐ฌ๐ฑ ๐๐ค๐ง ๐ฑ% ๐๐ง๐ค๐ฌ๐ฉ๐
Correct:
๐ญ.๐ฌ๐ฑ
❌ ๐๐๐จ๐ฉ๐๐ ๐ ๐ฎ: ๐๐จ๐๐ฃ๐ ๐ฌ.๐ฎ๐ฌ ๐๐ค๐ง ๐ฎ๐ฌ% ๐ฟ๐๐๐ง๐๐๐จ๐
Correct:
๐ฌ.๐ด๐ฌ
❌ ๐๐๐จ๐ฉ๐๐ ๐ ๐ฏ: ๐พ๐๐๐๐ ๐๐ฃ๐ ๐ฟ๐๐๐๐๐ง๐๐ฃ๐๐๐จ ๐๐ฃ๐จ๐ฉ๐๐๐ ๐๐ ๐๐๐ฉ๐๐ค๐จ
For exponential tables, divide consecutive values.
❌ ๐๐๐จ๐ฉ๐๐ ๐ ๐ฐ: ๐๐๐ฃ๐ค๐ง๐๐ฃ๐ ๐๐๐ข๐ ๐๐ฃ๐๐ฉ๐จ
“Doubles every 5 years” does not mean it doubles every year.
❌ ๐๐๐จ๐ฉ๐๐ ๐ ๐ฑ: ๐๐๐ญ๐๐ฃ๐ ๐๐ฅ ๐๐ฉ๐๐ง๐ฉ๐๐ฃ๐ ๐๐๐ก๐ช๐ ๐ผ๐ฃ๐ ๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐๐๐ฉ๐ค๐ง
In:
๐(๐) = ๐ฑ๐ฌ(๐ญ.๐ฌ๐ฐหฃ)
50 is the starting value.
1.04 is the growth factor.
✦ ๐ฏ๐ฏ. ๐๐๐จ๐ฉ ๐๐๐ฉ ๐๐ฉ๐ง๐๐ฉ๐๐๐ฎ
When you see an exponential question, stop before calculating.
Ask these questions:
① ๐๐๐๐ฉ ๐๐จ ๐ฉ๐๐ ๐จ๐ฉ๐๐ง๐ฉ๐๐ฃ๐ ๐ซ๐๐ก๐ช๐?
② ๐๐๐๐ฉ ๐๐จ ๐ฉ๐๐ ๐ข๐ช๐ก๐ฉ๐๐ฅ๐ก๐๐๐ง?
③ ๐๐จ ๐๐ฉ ๐๐ง๐ค๐ฌ๐ฉ๐ ๐ค๐ง ๐๐๐๐๐ฎ?
④ ๐๐๐๐ฉ ๐๐ค๐๐จ ๐ ๐ง๐๐ฅ๐ง๐๐จ๐๐ฃ๐ฉ?
⑤ ๐๐ค๐ฌ ๐ข๐๐ฃ๐ฎ ๐ฉ๐๐ข๐๐จ ๐๐จ ๐ฉ๐๐ ๐๐๐๐ฉ๐ค๐ง ๐๐ฅ๐ฅ๐ก๐๐๐?
If you answer those five questions, many apparently difficult problems become much simpler.
✦ ๐ฏ๐ฐ. ๐๐ช๐๐๐ ๐๐ผ๐ ๐๐ง๐๐๐ฉ๐๐๐
๐๐ช๐๐จ๐ฉ๐๐ค๐ฃ ๐ญ
Which equation represents exponential growth?
๐ผ) ๐ = ๐ฏ๐ + ๐ฎ
๐ฝ) ๐ = ๐ฏ๐² + ๐ฎ
๐พ) ๐ = ๐ฏ(๐ญ.๐ฑหฃ)
๐ฟ) ๐ = ๐ฏ⁄๐
๐ผ๐ฃ๐จ๐ฌ๐๐ง: ๐พ
The variable appears in the exponent and the base is greater than 1.
๐๐ช๐๐จ๐ฉ๐๐ค๐ฃ ๐ฎ
A quantity increases by 12% each year.
What is the growth factor?
๐ผ๐ฃ๐จ๐ฌ๐๐ง: ๐ญ.๐ญ๐ฎ
Because:
๐ญ + ๐ฌ.๐ญ๐ฎ = ๐ญ.๐ญ๐ฎ
๐๐ช๐๐จ๐ฉ๐๐ค๐ฃ ๐ฏ
A quantity decreases by 35% each month.
What multiplier should be used?
๐ผ๐ฃ๐จ๐ฌ๐๐ง: ๐ฌ.๐ฒ๐ฑ
Because:
๐ญ − ๐ฌ.๐ฏ๐ฑ = ๐ฌ.๐ฒ๐ฑ
๐๐ช๐๐จ๐ฉ๐๐ค๐ฃ ๐ฐ
The values in a table are:
๐ฐ, ๐ญ๐ฎ, ๐ฏ๐ฒ, ๐ญ๐ฌ๐ด
What is the common ratio?
๐ผ๐ฃ๐จ๐ฌ๐๐ง: ๐ฏ
because:
๐ญ๐ฎ ÷ ๐ฐ = ๐ฏ
๐ฏ๐ฒ ÷ ๐ญ๐ฎ = ๐ฏ
๐ญ๐ฌ๐ด ÷ ๐ฏ๐ฒ = ๐ฏ
๐๐ช๐๐จ๐ฉ๐๐ค๐ฃ ๐ฑ
A quantity starts at 80 and doubles every 4 hours.
What is its value after 12 hours?
There are:
๐ญ๐ฎ ÷ ๐ฐ = ๐ฏ
doubling periods.
Therefore:
๐ด๐ฌ × ๐ฎ³
= ๐ด๐ฌ × ๐ด
= ๐ฒ๐ฐ๐ฌ
✦ ๐ฏ๐ฑ. ๐๐๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ ๐๐๐ข๐ค๐ง๐ฎ ๐พ๐๐ง๐
๐(๐) = ๐(๐หฃ)
๐ → starting value
๐ → repeated multiplier
๐ → number of steps
๐ > ๐ญ → growth
๐ฌ < ๐ < ๐ญ → decay
๐(๐ฌ) = ๐
๐% increase → ×(๐ญ + ๐)
๐% decrease → ×(๐ญ − ๐)
constant difference → linear
constant ratio → exponential
double → ×๐ฎ
triple → ×๐ฏ
half → ×๐ญ⁄๐ฎ
๐(๐ + ๐ญ) = ๐๐(๐)
✦ ๐ฏ๐ฒ. ๐๐ผ๐ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ๐จ ๐๐ผ๐
๐๐๐๐ฉ ๐๐จ ๐๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ช๐ฃ๐๐ฉ๐๐ค๐ฃ?
A function in which the variable appears in the exponent, commonly written:
๐(๐) = ๐(๐หฃ)
๐๐ค๐ฌ ๐๐ค ๐ ๐๐๐๐ฃ๐ฉ๐๐๐ฎ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ง๐ค๐ฌ๐ฉ๐?
Look at the base.
If:
๐ > ๐ญ
the function grows.
๐๐ค๐ฌ ๐๐ค ๐ ๐๐๐๐ฃ๐ฉ๐๐๐ฎ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐๐๐๐ฎ?
If:
๐ฌ < ๐ < ๐ญ
the function decays.
๐๐๐๐ฉ ๐๐จ ๐ฎ๐ฌ% ๐๐ง๐ค๐ฌ๐ฉ๐ ๐๐จ ๐ ๐๐๐๐ฉ๐ค๐ง?
๐ญ.๐ฎ
๐๐๐๐ฉ ๐๐จ ๐ฎ๐ฌ% ๐๐๐๐๐ฎ ๐๐จ ๐ ๐๐๐๐ฉ๐ค๐ง?
๐ฌ.๐ด
๐๐ค๐ฌ ๐๐ค ๐ ๐๐๐ฃ๐ ๐๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐ฅ๐๐ฉ๐ฉ๐๐ง๐ฃ ๐๐ฃ ๐ ๐ฉ๐๐๐ก๐?
Divide consecutive output values.
If the ratios remain the same, the pattern is exponential.
๐๐๐๐ฉ ๐๐จ ๐ฉ๐๐ ๐๐๐๐๐๐ง๐๐ฃ๐๐ ๐๐๐ฉ๐ฌ๐๐๐ฃ ๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก ๐๐ฃ๐ ๐ก๐๐ฃ๐๐๐ง ๐๐ง๐ค๐ฌ๐ฉ๐?
Linear growth repeatedly adds the same amount.
Exponential growth repeatedly multiplies by the same factor.
๐๐๐๐ฉ ๐๐ค๐๐จ ๐ ๐ข๐๐๐ฃ ๐๐ฃ ๐(๐) = ๐(๐หฃ)?
It is the starting value because:
๐(๐ฌ) = ๐
๐๐๐๐ฉ ๐๐ค๐๐จ ๐ ๐ข๐๐๐ฃ?
It is the multiplier applied whenever ๐ increases by one unit.
✦ ๐๐๐ฃ๐๐ก ๐๐๐ ๐๐๐ฌ๐๐ฎ
The easiest way to understand exponential functions is not to memorize dozens of separate examples.
Understand the pattern:
๐๐๐ฃ๐๐๐ง → ๐๐๐ ๐ฉ๐๐ ๐จ๐๐ข๐ ๐๐ข๐ค๐ช๐ฃ๐ฉ.
๐๐ญ๐ฅ๐ค๐ฃ๐๐ฃ๐ฉ๐๐๐ก → ๐ข๐ช๐ก๐ฉ๐๐ฅ๐ก๐ฎ ๐๐ฎ ๐ฉ๐๐ ๐จ๐๐ข๐ ๐๐๐๐ฉ๐ค๐ง.
When you see an exponential question, find:
๐ฉ๐๐ ๐จ๐ฉ๐๐ง๐ฉ๐๐ฃ๐ ๐ซ๐๐ก๐ช๐
๐ฉ๐๐ ๐ข๐ช๐ก๐ฉ๐๐ฅ๐ก๐๐๐ง
๐ฉ๐๐ ๐ฉ๐๐ข๐ ๐๐ฃ๐ฉ๐๐ง๐ซ๐๐ก
๐๐ฃ๐ ๐ฉ๐๐ ๐ฃ๐ช๐ข๐๐๐ง ๐ค๐ ๐ง๐๐ฅ๐๐๐ฉ๐๐ ๐๐๐๐ฃ๐๐๐จ.
Once those four pieces are clear, the equation usually becomes much easier to see.
๐๐๐ ๐ฉ๐๐ ๐๐๐๐ฉ๐ค๐ง. ๐๐๐๐ค๐๐ฃ๐๐ฏ๐ ๐ฉ๐๐ ๐ฅ๐๐ฉ๐ฉ๐๐ง๐ฃ. ๐๐๐๐ฃ ๐จ๐ค๐ก๐ซ๐.
other pages to explore
SAT MATH FORMULA SHEET FOR QUICK REFERENCE
ALGEBRA
SO;VING LINEAR EQUATIONS [PART 1]
SOLVING LINEAR EQUATIONS [PART II]
SYSTEM OF EQUATIONS [ PART I ]
SAT Systems of Equations: Part 2 — Hard Questions, Word Problems, Graphs, Parameters & SAT Tricks
PARAMETER QUESTIONS IN SYSTEMS OF LINEAR EQUATIONS
QUADRATIC EQUATIONS [PART I]
QUADRATIC EQUATIONS [PART II]
Linear Inequality
PERCENTAGES
PERCENTAGES [introduction]
PERCENTAGE INCREASE AND DECREASE
SUCCESSIVE PERCENTAGES DISCOUNT PROFIT LOSS
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